« Valeurs trigonométriques exactes » : différence entre les versions

Contenu supprimé Contenu ajouté
rédaction
rédaction
Ligne 136 :
| scope="row" | <math>\frac\pi{20}</math>
| align="center" | 9°
| align="center" | <math>\frac\sqrt28\left(1+\sqrt5+\sqrt{10-2\sqrt5}\right)</math>
| align="center" | <math>\frac\sqrt28\left(1+\sqrt5-\sqrt{10-2\sqrt5}\right)</math>
| align="center" | <math>(2+\sqrt5)\left(1-\sqrt{5-2\sqrt5}\right)-1</math>
|-
| scope="row" | <math>\frac{3\pi}{20}</math>
| align="center" | 27°
| align="center" | <math>\frac\sqrt28\left(1-\sqrt5-\sqrt{10+2\sqrt5}\right)</math>
| align="center" | <math>\frac\sqrt28\left(1-\sqrt5+\sqrt{10+2\sqrt5}\right)</math>
| align="center" | <math></math>
|-
| scope="row" | <math>\frac{7\pi}{20}</math>
| align="center" | 63°
| align="center" | <math>\frac\sqrt28\left(1-\sqrt5+\sqrt{10+2\sqrt5}\right)</math>
| align="center" | <math>\frac\sqrt28\left(1-\sqrt5-\sqrt{10+2\sqrt5}\right)</math>
| align="center" | <math></math>
|-
| scope="row" | <math>\frac{9\pi}{20}</math>
| align="center" | 81°
| align="center" | <math>\frac\sqrt28\left(1+\sqrt5-\sqrt{10-2\sqrt5}\right)</math>
| align="center" | <math>\frac\sqrt28\left(1+\sqrt5+\sqrt{10-2\sqrt5}\right)</math>
| align="center" | <math></math>
|-