Annexe de niveau 14.
C 0 = 0 C 2 k + 1 = 4 Y m ( 2 k + 1 ) π C 2 k = 0 {\displaystyle {\begin{matrix}C_{0}&=&0\\C_{2k+1}&=&{\frac {4Y_{m}}{\left(2k+1\right)\pi }}\\C_{2k}&=&0\end{matrix}}}
